The Breakfast Club attendance

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Problem

This code checks a string called breakfastHours similar to

1567

which translates to Monday, Friday, Saturday, Sunday.

1 = Monday

2 = Tuesday

….

7 = Sunday

The user then checks the boxes for the days they visited the club, which is all handled within jQuery later on, with the chkB{0} tags.

 #region BuildOpeningHours
private string BuildOpeningHours() {

StringBuilder sb = new StringBuilder();
string hoursPrefix = "Opening";

if (listing.ListingTypeParentName == "restaurants-dining") {
//display opening hours
if (!String.IsNullOrEmpty(listing.BreakfastOpeningDays) || !String.IsNullOrEmpty(listing.LunchOpeningDays) || !String.IsNullOrEmpty(listing.DinnerOpeningDays)) {
sb.Append(OpeningHoursTable(listing.BreakfastOpeningDays, listing.LunchOpeningDays, listing.DinnerOpeningDays, listing.LateOpeningDays));
} else if (!String.IsNullOrEmpty(listing.OpeningHours)) {
sb.AppendFormat("<p itemprop="openingHours"">{0}</p>""

Solution

listing.OpeningHours);

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