Detect real “hard” character keys only

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Is there any simple way to detect user keystrokes that result in character input? In other words, ignore all soft keys and modifier keys? This works but seems sort of hacky:

var keycode = event.keyCode ? event.keyCode : event.charCode
if((keycode>=48 && keycode<=90) || (keycode>=96 && keycode<=111) || (keycode>=186 && keycode<=192) || (keycode>=219 && keycode<=222)){


Yes, use keypress events instead of keydown events. See example: – or a non-jquery example:

You can use String.fromCharCode in combination with a Regular Expression test as alernative:

var cando =  /[a-z0-9]/i
              .test(String.fromCharCode(event.keyCode || event.charCode));
if( cando ){

In the RegExp you can put all the characters you want to allow, in this case all a to z (case insensitive) and the digits 0 to 9. Best to use the keypress event here.

BTW, what kind of criterium is ‘seeming sort of hacky’?

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